NEC Chapter 9 Table 9 is the reference electricians and engineers use for accurate alternating-current voltage-drop and short-circuit calculations. This tool makes the table searchable: pick a conductor and conduit type to read the AC resistance and reactance per 1000 feet and compute the effective impedance.
How it works
Table 9 lists, for three single conductors in a raceway at 60 Hz, the inductive reactance and the AC resistance for copper and aluminum by conduit material. The effective impedance at a given power factor comes from the table footnote:
Ze = R · pf + X · sin(arccos(pf))
where R is the AC resistance, X is the reactance for the conduit type, and
pf is the load power factor. Multiplying Ze by circuit length and current
gives a far more accurate AC voltage drop than using DC resistance alone,
especially for large conductors where reactance dominates.
Worked example
A 250 kcmil copper conductor in steel conduit has roughly 0.052 Ω/kft AC resistance and 0.052 Ω/kft reactance. At 0.85 power factor:
Ze = 0.052 × 0.85 + 0.052 × sin(arccos(0.85))
= 0.052 × 0.85 + 0.052 × 0.527
≈ 0.044 + 0.027
≈ 0.071 Ω/kft
Over a 300-ft one-way run carrying 200 A, the voltage drop is:
VD = 0.071 Ω/kft × (300/1000) kft × 200 A ≈ 4.26 V
For a 480 V three-phase system that is less than 1% — acceptable. For a 120 V circuit the same absolute drop would be over 3.5%, which may violate the NEC Informational Note recommending 3% maximum for branch circuits.
Note that the same 250 kcmil in PVC conduit would show lower resistance and reactance than in steel, since steel’s magnetic properties increase both values. Always pick the conduit column that matches your actual raceway type.
Why Table 9 instead of Table 8 for AC circuits
Table 8 gives DC resistance and physical conductor properties. For direct-current systems and for short, low-current runs where reactance is negligible, it works well. But for AC circuits — particularly runs over 100 ft, circuits with large conductors, or high-current feeders — the combination of skin effect (raising effective resistance) and inductive reactance makes Table 8 values meaningfully inaccurate. Table 9 accounts for both effects at 60 Hz.
The reactance component becomes especially significant for conductors larger than about 2/0 AWG. For 500 kcmil or 750 kcmil conductors, reactance can be as large as the AC resistance, and ignoring it can cause a substantial underestimate of voltage drop.
Three-phase vs single-phase circuits
Table 9 values assume three single conductors in a raceway, which matches three-phase circuits directly. For single-phase two-wire circuits, the current flows out on one conductor and returns on the other — the effective circuit length for voltage drop is twice the one-way distance. Multiply your one-way run length by two before applying the Ze formula for single-phase calculations.
Notes
These figures are approximate reproductions for reference purposes. Steel conduit raises both AC resistance and reactance relative to PVC or aluminum. Verify against the current NEC Chapter 9 Table 9 in the edition adopted by your jurisdiction before submitting design documentation.