Chemical kinetics underpins everything from industrial reactor design to drug metabolism to food spoilage. This calculator consolidates six essential rate-of-reaction calculations in one place — no pen, paper, or spreadsheet required.
What it covers
| Mode | Formula | Typical use |
|---|---|---|
| Average rate | rate = −(1/s) · Δ[A]/Δt | Lab titration data |
| Initial rate (tangent) | r₀ ≈ ([A]₀ − [A]ₜ)/t | Determining rate laws from experiments |
| Arrhenius k | k = A · exp(−Ea/RT) | Predicting k at any temperature |
| Rate law | r = k[A]^m[B]^n | Computing rate from concentrations |
| Half-life | t½ = ln2/k or 1/(k[A]₀) | Decay and clearance problems |
| Activation energy | Ea = −R·ln(k₂/k₁)/(1/T₂−1/T₁) | Experimental Ea from two k/T pairs |
How it works
Average rate uses the standard definition: the negative of the concentration change of a reactant divided by the time interval and its stoichiometric coefficient. The sign convention ensures a positive rate whether you track a reactant falling or a product rising.
Initial rate approximates the tangent to the concentration–time curve at t = 0. Use the smallest measurable time interval for highest accuracy; the approximation improves as t approaches zero.
Arrhenius equation — k = A · exp(−Ea / RT) — takes the pre-exponential factor A (units match k), the activation energy Ea in J/mol, and the absolute temperature T in Kelvin. The universal gas constant R = 8.314 J mol⁻¹ K⁻¹ is built in.
Rate law evaluates r = k[A]^m[B]^n. Enter fractional or decimal orders; the calculator handles non-integer exponents (common in enzyme kinetics and heterogeneous catalysis).
Half-life covers both first-order (t½ = ln 2 / k, concentration-independent) and second-order (t½ = 1 / (k · [A]₀), which lengthens as the reaction proceeds).
Activation energy from two points rearranges the Arrhenius equation into its linear two-point form. Measure k at two temperatures T₁ and T₂ and the calculator returns Ea in both J/mol and kJ/mol.
Worked example — Arrhenius at 298 K and 350 K
A reaction has A = 1 × 10¹³ s⁻¹ and Ea = 75,000 J/mol.
At T = 298 K: k = 10¹³ × exp(−75000 / (8.314 × 298)) = 10¹³ × exp(−30.27) ≈ 0.713 s⁻¹
At T = 350 K: k = 10¹³ × exp(−75000 / (8.314 × 350)) = 10¹³ × exp(−25.77) ≈ 64.0 s⁻¹
Feeding those two k/T pairs into the activation energy mode returns Ea ≈ 75,000 J/mol — confirming the round-trip. Notice that a 52 K rise multiplied k by roughly 90×, illustrating why even modest temperature increases dramatically accelerate reactions with large Ea.
Formula reference
All six formulas use standard IUPAC notation. Concentrations are in mol L⁻¹ (molarity), temperatures in Kelvin, energies in J/mol, and time in seconds unless the rate constant units imply otherwise. The rate constant k carries composite units that depend on overall reaction order: s⁻¹ for first order, L mol⁻¹ s⁻¹ for second order, L² mol⁻² s⁻¹ for third order.
Every result includes a step-by-step working box so you can verify each arithmetic operation — useful for checking exam answers or debugging a lab calculation.